Looking for classes? Ksquare Career Institute, Bengaluru →
A bullet is fired from a gun at the speed of $280 m s^{-1}$ in the direction $30^{\circ}$ above the horizontal. The maximum height attained by the bullet is ($g = 9.8 m s^{-2}$, $\sin 30^{\circ} = 0.5$)
Explanation
Maximum height, $H = u^{2}\sin^{2} \theta/2g$ $H = (280)^{2} \times (\sin^{2} 30)/(2 \times 9.8) = (280 \times 280 \times 0.5 \times 0.5)/(2 \times 9.8)$ $\therefore H = 1000 m$