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If $t_{m}$ is the time taken by a projectile to achieve the maximum height, then the total time of flight $T_{f}$ related to $t_{m}$ as
Explanation
$V_{y} = u \sin \theta - gt_{m} = 0$ $\therefore t_{m} = (u_{y}\sin \theta)/g$ (time to reach the maximum height) Total time of flight $T_{f} = 2(u \sin \theta)/g \therefore T_{f} = 2t_{m}$