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If the angles of projection of a projectile with same initial velocity exceed or fall short of $45^{\circ}$ by equal amounts, then the ratio of horizontal ranges is
Explanation
For complementary angles of projection $(45^{\circ} + \alpha)$ and $(45^{\circ} - \alpha)$ with same initial velocity u, range R is same. $\theta_{1} + \theta_{2} = (45^{\circ} + \alpha) + (45^{\circ} - \alpha) = 90^{\circ}$