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A boat B is moving upstream with velocity $3 m/s$ with respect to ground. An observer standing on boat observes that a swimmer S is crossing the river perpendicular If river flow velocity is $4 m/s$ and swion of motion of boat. of width 100 m in 50sec, then [add image]
Explanation
$\vec{v}_{SB} = v\hat{j} = \vec{v}_{S} + 3\hat{i}$ $\vec{v}_{S} = v\hat{j} - 3\hat{i}$ and $v = 100/50 = 2 m/s$ $\therefore |\vec{v}_{S}| = \sqrt{(v^{2} + {(3)}^{2}} = \sqrt{(2^{2} + 9} = \sqrt{13} m/s$ Drift = $50 \times 3 = 150 m$
