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Two particles A, B are moving on two concentric circles of radii $R_{1}$ and $R_{2}$ with equal angular speed $\omega$. At $t = 0$, their positions and direction of motion are shown in the figure: The relative velocity $\overrightarrow{v_{A}} - \overrightarrow{v_{B}} at t = \frac{\pi}{2\omega}$ is given by: [add image]
Explanation
From, $\theta = \omega t = \omega(\pi/2\omega) = \pi/2$. So, both have completed quater circle [add image] Relative velocity, $v_{A} - v_{B} = \omega R_{1}(-\hat{i}) - \omega R_{2}(-i) = \omega(R_{2} - R_{1})i$
