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If $\theta$ is the angle between two vectors, then the resultant vector is maximum, when value of $\theta$ is
Explanation
Resultant vector of two vectors $\vec{A}$ & $\vec{B}$ inclined at an angle $\theta$, is given by $R = \sqrt{A^{2} + B^{2} + 2AB \cos \theta} \therefore$ if $\theta = 0^{\circ}$; $\cos 0^{\circ} = 1$ $\therefore R = \sqrt{A^{2} + B^{2} + 2AB} = \sqrt{{(A + B)}^{2}}$; $R = A + B$ This is the maximum resultant possible.