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A particle moves a distance x in time t according to equation $x = (t + 5)^{-1}$. The acceleration of particle is proportional to
Explanation
$x = 1/(t+5) \therefore v = dx/dt = -1/(t+5)^{2}$ $\therefore a = d^{2}x/dt^{2} = 2/(t + 5)^{3} = 2x^{3}$ Now $1/(t+5) \propto v^{1/2} \therefore 1/(t+5)^{3} \propto v^{3/2} \propto a$