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The displacement-time graphs of two particles A and B are straight lines making angles of $30^{\circ}$ and $60^{\circ}$ respectively with the time axis. If the velocity of A is $v_{A}$ and that of B is $v_{B}$, the value of $v_{A}/v_{B}$ is
Explanation
$v_{A} = \tan 30^{\circ}$ and $v_{B} = \tan 60^{\circ}$ $\therefore v_{A}/v_{B} = \tan 30^{\circ}/\tan 60^{\circ} = (1/\sqrt{3})/\sqrt{3} = 1/3$