Looking for classes? Ksquare Career Institute, Bengaluru →
A ball is released from the top of tower of height h metre. It takes T second to reach the ground. What is the position in (m) from the ground of the ball in $T/3 \text{second}$?
Explanation
In $T/3 \text{sec}$, the distance travelled = $\frac{1}{2} g (T/3)^{2} = h/9$ $\therefore$ Position of the ball from the ground = $h - h/9 = 8h/9 m$