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In one dimensional motion, instantaneous speed v satisfies $0 \leq v < v_{0}$
Explanation
In one dimensional motion, for the maximum and minimum displacement we must have the magnitude and direction of maximum velocity. As maximum velocity in positive direction is $v_{0}$, hence maximum velocity in opposite direction is also $-v_{0}$. Maximum displacement in one direction = $v_{0}T$ Maximum displacement in opposite directions = $-v_{0}T$. Hence, $-v_{0}T < x < v_{0}T$
