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A ball is thrown vertically downward with a velocity of $20 m/s$ from the top of a tower. It hits the ground after some time with a velocity of $80 m/s$. The height of the tower is: $(g = 10 m/s^{2})$
Explanation
Using $v^{2} = u^{2} + 2gh$ Height, $h = (v^{2} - u^{2})/2g = ((80)^{2} - (20)^{2})/(2 \times 10)$ = $(6400 - 400)/20 = 300 m$