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A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60 m, then the magnitude of displacement would be: (Given $\cos 135^{\circ} = -0.7$ ) [add image]
Explanation
From $\triangle AOB$ $AB/\sin 135 = OB/\sin 22.5$ $AB = (\sin 135 / \sin 22.5) OB$ $= \frac{\sin(135)}{\sin(22.5)}\frac{arc(AB)}{\frac{3\pi}{4}}$ $= \frac{\sin(45)}{\sin(22.5)} \times \frac{60 \times 4}{3\pi} = 47 m$