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Write the dimensions of $a \times b$ in the relation $E = (b - x^{2})/(at)$, where E is the energy, x is the displacement and t is time
Explanation
Here, b and $x^{2} = L^{2}$ have same dimensions. Also, $a = x^{2}/(E \times t) = L^{2}/((ML^{2}T^{-2})T) = M^{-1}T^{1}$. $a \times b = [M^{-1}L^{2}T^{1}]$