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A wire has a mass $0.3 \pm 0.003g$, radius $0.5 \pm 0.005mm$ and length $6 \pm 0.06cm$. The maximum percentage error in the measurement of its density is
Explanation
Density, $\rho = M/V = M/(\pi r^{2}\ell)$ $\therefore \Delta\rho/\rho \times 100 = [\Delta M/M + 2\Delta r/r + \Delta\ell/\ell] \times 100$ = $[0.003/0.3 + 2(0.005/0.5) + 0.06/6] \times 100 = 4$