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A physical quantity P is described by the relation $P = a^{1/2}b^{2}c^{3}d^{-4}$. If the relative errors in the measurement of a, b, c and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be:
Explanation
Given, $P = a^{1/2}b^{2}c^{3}d^{-4}$ Maximum relative error, $\Delta P/P = (1/2)(\Delta a/a) + 2(\Delta b/b) + 3(\Delta c/c) + 4(\Delta d/d)$ = $(1/2) \times 2 + 2 \times 1 + 3 \times 3 + 4 \times 5 = 32\%$