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If energy (E), velocity (V) and time (T) are chosen as the fundamental quantities, the dimensional formula of surface tension will be:
Explanation
Let surface tension $s = E^{a}V^{b} \cdot T^{c}$. $MLT^{-2}/L = (ML^{2}T^{-2})^{a}(L/T)^{b}(T)^{c}$ Equating the dimension of LHS and RHS. $ML^{0}T^{-2} = M^{a}L^{2a+b}T^{-2a-b+c} \Rightarrow a = 1$, $2a + b = 0$, $-2a - b + c = -2 \Rightarrow a = 1$, $b = -2$, $c = -2$ Hence, the dimensions of surface tension are $[EV^{-2}T^{-2}]$