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If E and G respectively denote energy and gravitational constant, then $E/G$ has the dimensions of
Explanation
Dimensional formula of energy $E = (1/2)mv^{2}$. $[E] = [M^{1}L^{2}T^{-2}]$ Dimensional formula of gravitational constant $G = Fr^{2}/(m_{1}m_{2})$. $[G] = [M^{-1}L^{3}T^{-2}]$ From eq. (i) & (ii) $\therefore E/G = [M^{1}L^{2}T^{-2}]/[M^{-1}L^{3}T^{-2}] = [M^{2}L^{-1}T^{0}]$. Numerical constant like, $1/2$, 1,2 or $2\pi$ has no dimension.