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In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is:
A
0.4
B
0.5
C
0.6
D
0.7
Detailed Solution
Total alleles = 2 × 1000 = 2000
Number of A alleles = (2 × 360) + 480 = 1200
Frequency of A $= \frac{1200}{2000} = 0.6$
Number of A alleles = (2 × 360) + 480 = 1200
Frequency of A $= \frac{1200}{2000} = 0.6$