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Evolution
Hardy-Weinberg Principle
8 questions from 8 papers, each with its answer.
- questions
- 8
- papers
- 8
- years asked, 2017–2026
- 2 of 10
- of Evolution
- 5.59%
Appears in
Concepts tested
- Factors disturbing equilibrium 2
- Allele frequency
- Conditions for genetic equilibrium
- Genotype frequencies at equilibrium
- genotype frequencies from allele frequency
- Hardy-Weinberg principle
- hardy-weinberg-2pq
All Questions
2026 Re-NEET 1 question
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A population of diploid organisms is at Hardy-Weinberg equilibrium. If the frequency of allele A is 0.1, the frequency of AA is ________.Reference: NCERT Class XII, page 121. Frequency of allele A = p = 0.1. At Hardy-Weinberg equilibrium, frequency of AA = $p^2=(0.1)^2=0.01$.
2019 1 question
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A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4 then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
2016 Phase II 1 question
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In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by:
2015 AIPMT-I 1 question
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A population will not exist in Hardy–Weinberg equilibrium ifHardy–Weinberg equilibrium is disturbed by mutation, gene flow, genetic drift, non-random mating and natural selection.
Selective mating is non-random mating, so the population will not be in equilibrium.
2014 AIPMT 1 question
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In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is:Total alleles = 2 × 1000 = 2000
Number of A alleles = (2 × 360) + 480 = 1200
Frequency of A $= \frac{1200}{2000} = 0.6$
2013 NEET 1 question
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The tendency of population to remain in genetic equilibrium may be disturbed by:Hardy–Weinberg equilibrium assumes random mating. Lack of random mating, like mutation, migration, drift and selection, disturbs it.
2005 AIPMT 1 question
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At a particular locus, frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium -According to the Hardy-Weinberg principle, in a large, randomly mating population at equilibrium, $p^2 + 2pq + q^2 = 1$.
Here $p$ = frequency of allele A = 0.6 and $q$ = frequency of allele a = 0.4.
$p^2$ = frequency of AA, $q^2$ = frequency of aa and $2pq$ = frequency of the heterozygotes Aa.
$2pq = 2 \times 0.6 \times 0.4$
$2pq = 0.48$
(Check: $p^2 = 0.36$, $q^2 = 0.16$, and $0.36 + 0.48 + 0.16 = 1$.)
2002 AIPMT 1 question
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In which condition, the gene ratio remains constant for any species : -The Hardy–Weinberg principle states that allele (gene) frequencies in a population remain constant from generation to generation if certain conditions are met.
These conditions are: a large population, random mating, and no mutation, no migration (gene flow), no genetic drift and no natural selection.
Sexual selection, mutation and gene flow all change gene frequencies.
So the gene ratio remains constant under random mating (along with the other conditions).