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How many different kinds of gametes will be produced by a plant having the genotype AABbCC ?
A
Three
B
Four
C
Nine
D
Two
Detailed Solution
The number of different kinds of gametes produced $= 2^n$, where $n$ is the number of heterozygous gene pairs.
In the genotype AABbCC, the gene pairs AA and CC are homozygous, and only Bb is heterozygous.
So n = 1.
Number of kinds of gametes $= 2^1 = 2$
The two kinds of gametes are ABC and AbC.
So the plant will produce two different kinds of gametes.
In the genotype AABbCC, the gene pairs AA and CC are homozygous, and only Bb is heterozygous.
So n = 1.
Number of kinds of gametes $= 2^1 = 2$
The two kinds of gametes are ABC and AbC.
So the plant will produce two different kinds of gametes.