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The genotypes of a Husband and Wife are $I^AI^B$ and $I^Ai$. Among the blood types of their children, how many different genotypes and phenotypes are possible?
Explanation
Four genotypes collapse into three phenotypes (A, AB, B).
Detailed Solution
Husband $I^AI^B$ × Wife $I^Ai$
Offspring: $I^AI^A$, $I^AI^B$, $I^Ai$, $I^Bi$
Number of genotypes = 4
$I^AI^A$ and $I^Ai$ = A; $I^AI^B$ = AB; $I^Bi$ = B
Number of phenotypes = 3
