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The products A and B obtained in the following reactions, respectively, are
$3ROH + PCl_3 \rightarrow 3RCl + A$
$ROH + PCl_5 \rightarrow RCl + HCl + B$
A
$H_3PO_4$ and $POCl_3$
B
$H_3PO_3$ and $POCl_3$
C
$POCl_3$ and $H_3PO_3$
D
$POCl_3$ and $H_3PO_4$