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Match the reagents (List - I) with the product (List - II) obtained from phenol. Choose the correct answer.
Column I
- A. (i) NaOH (ii) $CO_2$ (iii) $H^+$
- B. (i) Aqueous NaOH + $CHCl_3$ (ii) $H^+$
- C. Zn dust, $\Delta$
- D. $Na_2Cr_2O_7$, $H_2SO_4$
Column II
- I. Benzoquinone
- II. Benzene
- III. Salicylaldehyde
- IV. Salicylic acid
Correct answer: A → IV, B → III, C → II, D → I
Detailed Solution
(a) Kolbe's reaction: sodium phenoxide + $CO_2$, then $H^+$ gives salicylic acid. (b) Reimer-Tiemann reaction ($CHCl_3$/aq. NaOH, then $H^+$) gives salicylaldehyde. (c) Phenol with zinc dust on heating gives benzene. (d) Oxidation with $Na_2Cr_2O_7/H_2SO_4$ gives benzoquinone.