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Reaction of phenol with chloroform in presence of dilute sodium hydroxide finally introduces which one of the following functional group?
A
$-CHCl_2$
B
$-CHO$
C
$-CH_2Cl$
D
$-COOH$
Detailed Solution
This is the Reimer–Tiemann reaction: phenol + $CHCl_3$ + NaOH, followed by acidification, gives salicylaldehyde (o-hydroxybenzaldehyde).
So a –CHO group is introduced.
So a –CHO group is introduced.
