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Reduction by $LiAlH_4$ of hydrolysed product of an ester gives :
A
Two alcohols
B
Two aldehydes
C
One acid and one alcohol
D
Two acids
Detailed Solution
Hydrolysis of an ester gives a carboxylic acid and an alcohol: $RCOOR' + H_2O \rightarrow RCOOH + R'OH$
$LiAlH_4$ reduces the carboxylic acid to a primary alcohol: $RCOOH \xrightarrow{LiAlH_4} RCH_2OH$; the alcohol $R'OH$ remains unchanged.
So the final products are two alcohols, $RCH_2OH$ and $R'OH$.
$LiAlH_4$ reduces the carboxylic acid to a primary alcohol: $RCOOH \xrightarrow{LiAlH_4} RCH_2OH$; the alcohol $R'OH$ remains unchanged.
So the final products are two alcohols, $RCH_2OH$ and $R'OH$.