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The following two reactions give the same foul smelling product Z.
X and Z, respectively, are:
X and Z, respectively, are:
A
$X = AgCN$; $Z = C_2H_5CN$
B
$X = KCN$; $Z = C_2H_5CN$
C
$X = KCN$; $Z = C_2H_5NC$
D
$X = AgCN$; $Z = C_2H_5NC$
Detailed Solution
$CH_3-CH_2-Cl \xrightarrow{AgCN\ (X)} CH_3-CH_2-NC$ (Z, ethyl isocyanide – AgCN is covalent, so attack is through N)
$C_2H_5-CO-NH_2 \xrightarrow{Br_2/NaOH} C_2H_5NH_2$ (Y, Hofmann bromamide degradation)
$C_2H_5NH_2 \xrightarrow[\Delta]{CHCl_3/ethanolic\ KOH} C_2H_5NC$ (Z, carbylamine reaction – foul smell)
So X = AgCN and Z = $C_2H_5NC$.