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Given below are two statements:
Statement-I: Oxidation of p-nitrotoluene with acidic $KMnO_4$ gives an acid that is stronger than benzoic acid.
Statement-II: Reduction of p-nitrotoluene with Sn/HCl followed by neutralization gives an amine that is more basic than aniline.
In light of the above statements, choose the most appropriate answer from the options given below.
Detailed Solution
S-I: p-nitrotoluene $\xrightarrow{KMnO_4/H^+}$ p-nitrobenzoic acid, which is a stronger acid than benzoic acid (electron-withdrawing $-NO_2$) - correct. S-II: p-nitrotoluene $\xrightarrow{Sn/HCl}$ p-toluidine, which is more basic than aniline (electron-donating $-CH_3$) - correct.