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The correct order of bond angles in the following compounds/species is:
Detailed Solution
$CO_2$: $180^\circ$; $NH_4^+$: $109.5^\circ$; $NH_3$: $107^\circ$ (one lone pair on N); $H_2O$: $104.5^\circ$ (two lone pairs on O). Lone pair-lone pair repulsion decreases the angle in water the most.