Solution

F.C. = (valence electrons in free atom) $-$ (non-bonding electrons) $- \frac{1}{2}$(bonding electrons) O-2: $6 - 4 - \frac{1}{2}(4) = 0$ O-1: $6 - 2 - \frac{1}{2}(6) = +1$ O-3: $6 - 6 - \frac{1}{2}(2) = -1$ So formal charges on O-2, O-1 and O-3 are 0, +1, $-1$.

Chemical Bonding and Molecular Structure in past papers

108 questions from this chapter have appeared across 27 exam years.