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The correct order of energies of molecular orbitals of $N_2$ molecule is:
A
$\sigma1s<\sigma^*1s<\sigma2s<\sigma^*2s<(\pi2p_x=\pi2p_y)<(\pi^*2p_x=\pi^*2p_y)<\sigma2p_z<\sigma^*2p_z$
B
$\sigma1s<\sigma^*1s<\sigma2s<\sigma^*2s<(\pi2p_x=\pi2p_y)<\sigma2p_z<(\pi^*2p_x=\pi^*2p_y)<\sigma^*2p_z$
C
$\sigma1s<\sigma^*1s<\sigma2s<\sigma^*2s<\sigma2p_z<(\pi2p_x=\pi2p_y)<(\pi^*2p_x=\pi^*2p_y)<\sigma^*2p_z$
D
$\sigma1s<\sigma^*1s<\sigma2s<\sigma^*2s<\sigma2p_z<\sigma^*2p_z<(\pi2p_x=\pi2p_y)<(\pi^*2p_x=\pi^*2p_y)$
Explanation
For $N_2$ (fewer than 15 electrons) the $\pi2p$ orbitals lie below $\sigma2p_z$.
Detailed Solution
$\sigma1s<\sigma^*1s<\sigma2s<\sigma^*2s<(\pi2p_x=\pi2p_y)<\sigma2p_z<(\pi^*2p_x=\pi^*2p_y)<\sigma^*2p_z$ is the correct order of energy of MO for homo nuclear diatomic species $N_2$.