Looking for classes? Ksquare Career Institute, Bengaluru →
Bond order of 1.5 is shown by:
A
$O_2$
B
$O_2^+$
C
$O_2^-$
D
$O_2^{2-}$
Detailed Solution
Bond order $= \frac{1}{2}(N_b - N_a)$
$O_2$ (16 e⁻): $\frac{1}{2}(10 - 6) = 2$
$O_2^+$ (15 e⁻): $\frac{1}{2}(10 - 5) = 2.5$
$O_2^-$ (17 e⁻): $\frac{1}{2}(10 - 7) = 1.5$
$O_2^{2-}$ (18 e⁻): $\frac{1}{2}(10 - 8) = 1$
So $O_2^-$ has bond order 1.5.
$O_2$ (16 e⁻): $\frac{1}{2}(10 - 6) = 2$
$O_2^+$ (15 e⁻): $\frac{1}{2}(10 - 5) = 2.5$
$O_2^-$ (17 e⁻): $\frac{1}{2}(10 - 7) = 1.5$
$O_2^{2-}$ (18 e⁻): $\frac{1}{2}(10 - 8) = 1$
So $O_2^-$ has bond order 1.5.