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The correct geometry and hybridization for $XeF_4$ are:
A
Planar triangle, $sp^3d^3$
B
square planar, $sp^3d^2$
C
octahedral, $sp^3d^2$
D
trigonal bipyramidal, $sp^3d$
Explanation
4 bond pairs + 2 lone pairs → $sp^3d^2$, octahedral arrangement.
Detailed Solution
$XeF_4$ is of type $AB_4L_2$ → $sp^3d^2$ hybridisation
Geometry (electron-pair arrangement) → octahedral; shape → square planar
Note: the source key marks 'octahedral, $sp^3d^2$' (electron-pair geometry); the molecular shape of $XeF_4$ is square planar, which is also listed as an option.
Geometry (electron-pair arrangement) → octahedral; shape → square planar
Note: the source key marks 'octahedral, $sp^3d^2$' (electron-pair geometry); the molecular shape of $XeF_4$ is square planar, which is also listed as an option.