Looking for classes? Ksquare Career Institute, Bengaluru →
Which plot of $\ln k$ vs $\frac{1}{T}$ is consistent with Arrhenius equation?
A
- 
B
- 
C
- 
D
- 
Detailed Solution
Arrhenius equation: $k = Ae^{-E_a/RT}$
$\ln k = \ln A - \frac{E_a}{R}\left(\frac{1}{T}\right)$
This is a straight line ($y = mx + c$) with slope $-\frac{E_a}{R}$ (negative) and intercept $\ln A$ (positive).
So the plot of $\ln k$ vs $\frac{1}{T}$ is a straight line with a negative slope.
$\ln k = \ln A - \frac{E_a}{R}\left(\frac{1}{T}\right)$
This is a straight line ($y = mx + c$) with slope $-\frac{E_a}{R}$ (negative) and intercept $\ln A$ (positive).
So the plot of $\ln k$ vs $\frac{1}{T}$ is a straight line with a negative slope.