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The order of energy absorbed which is responsible for the color of complexes
A. $[Ni(H_2O)_2(en)_2]^{2+}$
B. $[Ni(H_2O)_4(en)]^{2+}$ and
C. $[Ni(en)_3]^{2+}$
is
A
B > A > C
B
A > B > C
C
C > B > A
D
C > A > B
Detailed Solution
en (ethylenediamine) is a stronger field ligand than $H_2O$.
As the number of en ligands increases, the crystal field splitting $\Delta_o$ increases, so the energy absorbed increases.
$[Ni(en)_3]^{2+}$ (3 en) > $[Ni(H_2O)_2(en)_2]^{2+}$ (2 en) > $[Ni(H_2O)_4(en)]^{2+}$ (1 en)
So the order is C > A > B.