2023 ElectrochemistryConductance of Electrolytic Solutions – Cell Constant Easy Question 10 of 74 in Electrochemistry

The conductivity of centimolar solution of KCl at $25^\circ C$ is $0.0210\ ohm^{-1}cm^{-1}$ and the resistance of the cell containing the solution at $25^\circ C$ is 60 ohm. The value of cell constant is:

A $3.34\ cm^{-1}$
B $1.34\ cm^{-1}$
C $3.28\ cm^{-1}$
D $1.26\ cm^{-1}$

The answer is D.

Solution

Cell constant $=\text{conductivity}\times\text{resistance}=0.0210\times60=1.26\ cm^{-1}$.

Conductivity = Conductance × Cell constant Conductivity = (1/resistance) × Cell constant Cell constant = Conductivity × Resistance Cell constant $=0.0210\times60=1.26\ cm^{-1}$

Concept cell constant = conductivity × resistance

Electrochemistry in past papers

74 questions from this chapter have appeared across 27 exam years.