2024 ElectrochemistryFaraday's First Law - Mass Deposited by Electrolysis Medium Question 7 of 74 in Electrochemistry

Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is: (Given: Molar mass of $Cu$: 63 g $mol^{-1}$, 1F = 96487 C)

A 31.5 g
B 0.0315 g
C 3.15 g
D 0.315 g

The answer is D.

Solution

$W = \frac{E}{96487} \times I \times t$, with equivalent mass of Cu $E = \frac{63}{2}$ $W = \frac{63/2}{96487} \times 9.6487 \times 100$ $W = 0.315$ g

Concept Calculating mass deposited using Q = It and Faraday's constant

Electrochemistry in past papers

74 questions from this chapter have appeared across 27 exam years.