When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity required to completely oxidise MnO₄²⁻ to MnO₄⁻ is:

1 2014 AIPMT ElectrochemistryFaraday's laws Easy
When 0.1 mol $MnO_4^{2-}$ is oxidised the quantity of electricity required to completely oxidise $MnO_4^{2-}$ to $MnO_4^-$ is:
A 96500 C
B $2\times96500$ C
C 9650 C
D 96.50 C

Detailed Solution

$MnO_4^{2-} \rightarrow MnO_4^- + e^-$ (Mn goes from +6 to +7)
0.1 mol needs 0.1 mol of electrons = 0.1 F
Charge = 0.1 × 96500 = 9650 C

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