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The weight of silver (at. wt. = 108) displaced by a quantity of electricity which displaces 5600 mL of $O_2$ at STP will be:
A
5.4 g
B
10.8 g
C
54.9 g
D
108.0 g
Detailed Solution
Faraday's second law: $\frac{w_{Ag}}{E_{Ag}} = \frac{w_{O_2}}{E_{O_2}}$
$\frac{w_{Ag}}{108} = \frac{\frac{5600}{22400}\times32}{8}$
$w_{Ag} = 108$ g
$\frac{w_{Ag}}{108} = \frac{\frac{5600}{22400}\times32}{8}$
$w_{Ag} = 108$ g
