H₂C=CH-CH(CH₃)-CH₃ + HBr → (X)Here (X) (predominantly) is :

$H_2C=CH-CH(CH_3)-CH_3 + HBr \rightarrow (X)$
Here (X) (predominantly) is :
A $CH_3-CH(Br)-CH(CH_3)-CH_3$
B $CH_3-CH(CH_3)-CH(Br)-CH_3$
C $CH_3-CH(CH_3)-CH_2-CH_2Br$
D $CH_3-C(Br)(CH_3)-CH_2CH_3$

Detailed Solution

The alkene is 3-methylbut-1-ene. The addition of HBr is an electrophilic addition that proceeds through a carbocation.
Step 1: $H^+$ adds to the terminal $CH_2$ carbon (Markovnikov's rule) to give a secondary carbocation.
$CH_2=CH-CH(CH_3)-CH_3 + H^+ \rightarrow CH_3-\overset{+}{C}H-CH(CH_3)-CH_3$ ($2^\circ$ carbocation, less stable)
Step 2: a 1,2-hydride shift from the adjacent carbon converts it into a more stable tertiary carbocation.
$CH_3-\overset{+}{C}H-CH(CH_3)-CH_3 \xrightarrow{1,2\text{-hydride shift}} CH_3-CH_2-\overset{+}{C}(CH_3)-CH_3$ ($3^\circ$ carbocation, more stable)
Step 3: $Br^-$ attacks the tertiary carbocation.
$CH_3-CH_2-\overset{+}{C}(CH_3)_2 + Br^- \rightarrow CH_3-C(Br)(CH_3)-CH_2CH_3$
The major product (X) is 2-bromo-2-methylbutane, $CH_3-C(Br)(CH_3)-CH_2CH_3$.

Electrophilic addition to alkenes in past papers

3 questions from this chapter have appeared across 3 exam years.

Keep going

Practise Electrophilic addition to alkenes All 3 questions This chapter in 2008 AIPMT