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What is the hybridization shown by $C_1$ and $C_2$ carbons, respectively in the given compound?
$OHC-CH=CH-CH_2COOCH_3$
Detailed Solution
The ester group has higher priority than the aldehyde, so numbering starts from the ester carbon: $\overset{5}{O}HC-\overset{4}{C}H=\overset{3}{C}H-\overset{2}{C}H_2-\overset{1}{C}OOCH_3$. $C_1$ is the ester carbonyl carbon ($sp^2$) and $C_2$ is the $CH_2$ carbon ($sp^3$).