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The correct decreasing order of oxidation state of the underlined atom in each molecule is
Detailed Solution
$\underline{N}_2O_5$: $2x+5(-2)=0 \Rightarrow x=+5$. $\underline{Al}_2O_3$: $2x+3(-2)=0 \Rightarrow x=+3$. $H_2\underline{S}$: $2(+1)+x=0 \Rightarrow x=-2$. So $N_2O_5>Al_2O_3>H_2S$.