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The correct order of N-compounds in its decreasing order of oxidation states is
Explanation
N is +5, +2, 0 and –3 in $HNO_3$, NO, $N_2$ and $NH_4Cl$.
Detailed Solution
Oxidation state of N: $HNO_3$ (+5), NO (+2), $N_2$ (0), $NH_4Cl$ (–3)
So the decreasing order is $HNO_3$, NO, $N_2$, $NH_4Cl$.