6.02×10²⁰ molecules of urea are present in 100 mL of its solution. The concentration of solution is:

37 2013 NEET SolutionsMolarity Easy
$6.02\times10^{20}$ molecules of urea are present in 100 mL of its solution. The concentration of solution is:
A 0.1 M
B 0.02 M
C 0.01 M
D 0.001 M

Detailed Solution

Number of moles $= \frac{6.02\times10^{20}}{6.02\times10^{23}} = 10^{-3}$ mol
Molar concentration $= \frac{n\times1000}{V_{solution}(mL)} = \frac{10^{-3}\times1000}{100} = 0.01$ M

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