Looking for classes? Ksquare Career Institute, Bengaluru →
Chemistry
Solutions
62 questions, each with its answer.
-
$6.02\times10^{20}$ molecules of urea are present in 100 mL of its solution. The concentration of solution is:Number of moles $= \frac{6.02\times10^{20}}{6.02\times10^{23}} = 10^{-3}$ mol
Molar concentration $= \frac{n\times1000}{V_{solution}(mL)} = \frac{10^{-3}\times1000}{100} = 0.01$ M
That is every easy question from 2013 NEET in Solutions.
Want a score?
Answers here are not saved. Practise as a test to be marked and see your progress.
Practise as a test