Solution

Percentage of C = 100 $-$ 32 $-$ 20 = 48% A: $\frac{32}{64} = \frac{1}{2}$ ; B: $\frac{20}{40} = \frac{1}{2}$ ; C: $\frac{48}{32} = \frac{3}{2}$ Simplest ratio A : B : C = 1 : 1 : 3 Empirical formula = $ABC_3$

Concept Calculating empirical formula from mass percent and atomic mass

Some Basic Concepts of Chemistry in past papers

49 questions from this chapter have appeared across 23 exam years.