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Some Basic Concepts of Chemistry
Stoichiometry of Acid-Base Neutralisation
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2024 1 question
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1 gram of sodium hydroxide was treated with 25 mL of 0.75 M $HCl$ solution, the mass of sodium hydroxide left unreacted is equal toMoles of NaOH in 1 g $= \frac{1}{40} = 0.025$ mol Moles of HCl in 25 mL $= \frac{0.75 \times 25}{1000} = 0.01875$ mol NaOH and HCl react 1 : 1, so moles of NaOH unreacted $= 0.025 - 0.01875 = 0.00625$ mol Mass of NaOH unreacted $= 0.00625 \times 40 = 0.25$ g $= 250$ mg