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A vessel contains 3.2 g of dioxygen gas at STP (273.15 K and 1 atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes one third of the original pressure. The volume of new vessel in L is: (Given - molar volume at STP is 22.4 L)
Detailed Solution
Moles of $O_2=\frac{3.2}{32}=0.1$ mol. Volume at STP $=0.1\times22.4=2.24$ L. By Boyle's law, $P_1V_1=P_2V_2 \Rightarrow 1\times2.24=\frac{1}{3}V_2 \Rightarrow V_2=6.72$ L.