Looking for classes? Ksquare Career Institute, Bengaluru →
The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is
A
5, 1, 0, $+\frac{1}{2}$
B
5, 1, 1, $+\frac{1}{2}$
C
6, 0, 0, $+\frac{1}{2}$
D
5, 0, 0, $+\frac{1}{2}$
Detailed Solution
Rb (Z = 37): $[Kr]5s^1$
The valence electron is in the 5s orbital: n = 5, l = 0 (s orbital), m = 0, s = $+\frac{1}{2}$
The valence electron is in the 5s orbital: n = 5, l = 0 (s orbital), m = 0, s = $+\frac{1}{2}$