Looking for classes? Ksquare Career Institute, Bengaluru →
The orbital angular momentum of a p-electron is given as:
A
$\sqrt6\,\frac{h}{2\pi}$
B
$\frac{h}{\sqrt2\pi}$
C
$\sqrt3\,\frac{h}{2\pi}$
D
$\sqrt{\frac{3}{2}}\,\frac{h}{\pi}$
Detailed Solution
Orbital angular momentum $= \sqrt{l(l+1)}\,\frac{h}{2\pi}$
For a p-electron l = 1: $\sqrt{1(1+1)}\,\frac{h}{2\pi} = \sqrt2\times\frac{h}{2\pi}$
$= \frac{h}{\sqrt2\pi}$
For a p-electron l = 1: $\sqrt{1(1+1)}\,\frac{h}{2\pi} = \sqrt2\times\frac{h}{2\pi}$
$= \frac{h}{\sqrt2\pi}$