The coagulation values in millimoles per litre of the electrolytes used for the coagulation of $As_2S_3$ are given below: I. (NaCl) = 52, II. ($BaCl_2$) = 0.69, III. ($MgSO_4$) = 0.22. The correct order of their coagulating power is

A III > II > I

B III > I > II

C I > II > III

D II > I > III

The answer is A.

Solution

Lower coagulation value = higher coagulating power.

Coagulating power $\propto \frac{1}{coagulation\ value}$
So the order is III > II > I.

Concept coagulating-power-inverse-value

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